读数脚本改用完整传导视图，与候选卡一致

候选卡判「所在环节被指向」时认的是两张视图取或，读数脚本原先只读了含已启动成员
的那张窄视图，算出来的乙路覆盖比卡上真实看到的低。一只票挂多个环节时取第一个
评析过的那个。

Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>

logic_state_coverage.py

@@ -151,11 +151,15 @@ def main(ds: str | None = None, plan_day: str | None = None) -> None:
         if name:
             by_seg[name] = r
     seg_of = {}
+    # 用完整的传导视图，不是只含已启动成员的那张。候选卡判"所在环节被指向"时认的就是
+    # 完整这张（plan.py 的 evd["pointed"] 是两张视图取或），读数脚本必须跟它一致，
+    # 否则算出来的乙路覆盖比卡上真实看到的低。
+    # 一只票可能挂在多个环节上，这里保留全部，只要有一个环节评析过就算对上。
     try:
-        d = db.read_pg("SELECT ts_code, target FROM v_factor_transmission_moved "
+        d = db.read_pg("SELECT ts_code, target FROM v_factor_transmission "
                        "WHERE scan_date = %s", (ds,))
         for r in d.itertuples():
-            seg_of[common.to_prefix(str(r.ts_code).strip())] = str(r.target)
+            seg_of.setdefault(common.to_prefix(str(r.ts_code).strip()), []).append(str(r.target))
     except Exception as e:  # noqa: BLE001
         print(f"  （传导视图读取失败，乙路整体缺席: {e!r}）")
 
@@ -165,7 +169,9 @@ def main(ds: str | None = None, plan_day: str | None = None) -> None:
     samples: dict = {}
     for k in codes:
         a = ls.from_claims(claims.get(k), ds, stale_days=config.LOGIC_STALE_DAYS)
-        b = ls.from_judgement(by_seg.get(seg_of.get(k, "")))
+        # 一只票挂在多个环节上时，取第一个评析过的那个环节的研判。
+        row = next((by_seg[t] for t in seg_of.get(k, []) if t in by_seg), None)
+        b = ls.from_judgement(row)
         c = brokers.get(k) or ls.signal(ls.PATH_BROKER, ls.SIG_NONE,
                                         why="两个窗口里算不出可比的预测")
         per_path[ls.PATH_CLAIM][a["signal"]] += 1